Namrata participates on average in 38 client meetings per month with a standard deviation of 8.2 meetings. Suppose
Namrata's number of client meetings per month are normally distributed. Let X = the number of client meetings in a
particular month. Then X~ N(38, 8.2).
If necessary, round to three decimal places.
Provide your answer below:
Suppose Namrata participates in 34 client meetings in the month of October. The z-score when x = 34 is
mean is
This z-score tells you that x = 34 is standard deviations to the left of the mean.
The
