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From the following balanced molecular equation, write the net ionic equation. K2C2O4(aq) Ba(OH)2(aq) ⟶ 2KOH(aq) BaC2O4(s)
A. 2K (aq) C2O42-(aq) Ba2 (aq) 2OH-(aq) ⟶ 2K(OH)2(s) BaC2O4(s)
B. 2K (aq) 2OH-(aq) ⟶ 2K(OH)2(s)
C. C2O42-(aq) Ba2 (aq) ⟶ BaC2O4(s)
D. 2K (aq) C2O42-(aq) ⟶ K2C2O4(s)



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