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Given the following thermochemical equations:

6C(graphite) + 3H2(g) → C6H6(l) ΔH° = 49.0 kJ

C(graphite) + O2(g) → CO2(g) ΔH° = -393.5 kJ

2H2(g) + O2(g) → 2H2O(l) ΔH° = - 571.6 kJ



Calculate ΔH° for the following reaction:

2C6H6(l) + 15O2(g) → 12CO2(g)+ 6H2O(l) ΔH° = ?
Question 9 options:

-1260.6 kJ

-5195.6 kJ

+1260.6 kJ

-6534.8 kJ

-6338.8 kJ



Answer :

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