Find the following indefinite integral:
integral open parentheses 12 e to the power of x minus 7 to the power of x plus 7 x to the power of 5 close parentheses d x
a) 12 e to the power of x minus fraction numerator 7 to the power of x over denominator ln 7 end fraction plus 7 over 6 x to the power of 6 plus c
b) 12 e to the power of x plus fraction numerator 7 to the power of x over denominator ln x end fraction plus 7 over 5 x to the power of 6 plus c
c) 12 e to the power of x plus 7 to the power of x ln 7 plus 7 over 6 x to the power of 6 plus c
d) 12 e to the power of x minus 7 to the power of x ln x plus 7 over 5 x to the power of 6 plus c