]Given tan θ = -[tex]\frac{1}{3}[/tex] and cos θ > 0 , find csc θ and sec θ
A) csc θ = -3 and sec θ = [tex]\frac{3\sqrt{10} }{10}[/tex]
B)csc θ = -10 and sec θ = [tex]\frac{10}{3}[/tex]
C) csc θ =[tex]\sqrt{10}[/tex] and sec θ
-[tex]\frac{\sqrt{10} }{3}[/tex] D) csc θ = -[tex]\sqrt{10}[/tex] and sec θ = [tex]\frac{\sqrt{10} }{3}[/tex]