Determine u and dv in the Integration By Parts for ∫ ln(x)tan⁻¹(x)dx
A) u = sec²(x), dv = (1)/(x)dx
B) u = (1)/(x), dv = sec²(x)dx
C) u = tan⁻¹(x),dv=ln(x)dx
D) u = ln(x), dv = tan⁻¹(x)dx