11.2 In the diagram, ABCD is a parallelogram with on the diagonals BD and AC intersect in P. PC and PD intersect the circle at S and R respectively. T is a point on AP such that TP = PS. TR is drawn. B 52 S 2 T AP A 2 2 12 11.2.1 Prove that: (a) AT = SC R 2 2 1 D (2) (b) APSR ||| APBA (5) PR TR 11.2.2 If it is further given that , prove that: PA AD (a) ARPT ||| AAPD (b) ATRD is a cyclic quadrilateral (3) (2) [18] ​