What mass of l₂ is produced by the reaction of 0.568 mole of CuCl₂ and excess Kl according to the following reaction?
2 CuCl₂ + 4 KI + 2 Cul + 4 KCI + l₂
a. 288 g
b. 0.284 g
c. 144 g
d. 72.18 g
e. 36.0 g



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