A reaction proceeds with 2.72 moles of magnesium chlorate and 3.14 moles of sodium hydroxide. This is the equation of the reaction: Mg(ClO_3)_2+2NaOHto Mg(OH)_2+2NaClO_3. Determine the theoretical amount of each product that the reaction will produce. The reaction will produce â–¡ of magnesium hydroxide and â–¡ of sodium chlorate. 1.36 moles Reset Next 1.57 moles 2. 72 moles 3. 14 moles 4. 52 moles



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