Answer :
First, create an equation with the criteria given.
If we let x be your number,
[tex]2(3x) = 80 + x + 10[/tex]
([tex]2(3x)[/tex] is twice the product of 3 and x, and if it exceeds [tex]x+80[/tex] by 10, then we add 10 to [tex]x+80[/tex] to make the two sides of the equation equal.)
Now, solve for [tex]x[/tex].
[tex]6x=90+x \\ 5x=90 \\ x=18[/tex]
If we let x be your number,
[tex]2(3x) = 80 + x + 10[/tex]
([tex]2(3x)[/tex] is twice the product of 3 and x, and if it exceeds [tex]x+80[/tex] by 10, then we add 10 to [tex]x+80[/tex] to make the two sides of the equation equal.)
Now, solve for [tex]x[/tex].
[tex]6x=90+x \\ 5x=90 \\ x=18[/tex]
