Answer :
[tex]\frac{1}{c} +5=\frac{2}{3}\ \|\ subtract\ 5\ to\ both\ sides \\\\\frac{1}{c} =\frac{2}{3}-5\\\\\frac{1}{c} =\frac{2}{3}-\frac{15}{3}\\\\\frac{1}{c} = \frac{-13}{3}\\\\-13c=3\ \ | \ divide \ both \ sides\ by\ (-13)\\\\c=-\frac{3}{13} [/tex]
[tex]\frac{1}{c+5} = \frac{2}{3} \\\\2(c+5) =3\\\\2c+10=3\ \ |\ subtract\ 10\ to\ both\ sides \\\\ 2c=3-10 \\\\2c=-7 \ \ | \ divide \ both \ sides\ by\ 2 \\\\c=-\frac{7}{2}\\\\c=-3.5 [/tex]
[tex]\frac{1}{c+5} = \frac{2}{3} \\\\2(c+5) =3\\\\2c+10=3\ \ |\ subtract\ 10\ to\ both\ sides \\\\ 2c=3-10 \\\\2c=-7 \ \ | \ divide \ both \ sides\ by\ 2 \\\\c=-\frac{7}{2}\\\\c=-3.5 [/tex]
