Answer :
Five half-full classes + three 3/4 full classes + 2 1/8 empty (which is 7/8 full) classes altogether give us 10 classes without 70 students. Let's assume that one class is x, so we can write it as:
5 * 1/2x + 3 * 3/4x + 2 * 7/8x = 10x - 70
After multiplying and changing it to decimals:
2,5x + 2,25x + 1,75x = 10x - 70
6,5x = 10x - 70 / - 6,5x (both sides)
0 = 3,5x - 70 / + 70 (both sides)
70 = 3,5x / :3,5 (both sides)
x = 20
Check:
5 * 1/2 * 20 + 3 * 3/4 * 20 + 2 * 7/8 * 20 = 10 * 20 - 70
5 * 10 + 3 * 15 + 2 * 17,5 = 200 - 70
50 + 45 + 35 = 130
130 = 130
Correct - there are 20 students in each class (200 students overall)
Answer: There are 200 students in the school when no students are absent.
5 * 1/2x + 3 * 3/4x + 2 * 7/8x = 10x - 70
After multiplying and changing it to decimals:
2,5x + 2,25x + 1,75x = 10x - 70
6,5x = 10x - 70 / - 6,5x (both sides)
0 = 3,5x - 70 / + 70 (both sides)
70 = 3,5x / :3,5 (both sides)
x = 20
Check:
5 * 1/2 * 20 + 3 * 3/4 * 20 + 2 * 7/8 * 20 = 10 * 20 - 70
5 * 10 + 3 * 15 + 2 * 17,5 = 200 - 70
50 + 45 + 35 = 130
130 = 130
Correct - there are 20 students in each class (200 students overall)
Answer: There are 200 students in the school when no students are absent.
The total number of students in the entire school when all students are present is 200 students.
Let the number of students in each class = n
We could set up an equation relating to the given scenario thus :
5(1/2n) + 3(3/4n) + 2(n - 1/8) = 10n - 70
5n/2 + 9n/4 + 2(7n/8) = 10n - 70
5n/2 + 9n/4 + 14n/8 = 10n - 70
L.C.M of 2, 4 and 8 = 8
(20n + 18n + 14n) /8 = (10n - 70)
Cross multiply :
52n = 8(10n - 70)
52n = 80n - 560
Subtract 80n from both sides:
52n - 80n = - 560
-28n = - 560
n = 560/28
n = 20
Hence, Number of students in each class = 20
Therefore, the total number of students in the entire school is 10n = 10 × 20 = 200 students
Learn more : https://brainly.com/question/18796573
