Answer :

[tex]-\frac{3}{4}+3\frac{1}{4}*1\frac{1}{5}= -\frac{3}{4}+\frac{13}{4}*\frac{6}{5}= \\ \\ =-\frac{3}{4}^{(5}+\frac{39}{10}^{(2}= \\ \\ =\frac{-15+78}{20}= \\ \\ =\boxed{\frac{63}{20}}[/tex]

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