Answer :
[tex]\frac{1}{2}x-\frac{3}{4}y=-2\ \ \ |Add\ \frac{3}{4}y\\\\
\frac{1}{2}x=-2+\frac{3}{4}y\ \ \ |Add\ 2\\\\
\frac{1}{2}x+2=\frac{3}{4}y\ \ |*\frac{4}{3}\\\\
y=\frac{4}{3}(\frac{1}{2}x+2)\\\\
\boxed{y=\frac{2}{3}x+\frac{8}{3}}[/tex]
