Answer :
[tex]\frac{1}{4}(3x-6)+\frac{1}{4}x=5\frac{1}{3}\\\\
\frac{3}{4}x-\frac{6}{4}+\frac{1}{4}x=\frac{16}{3}\ \ \ |Multiply\ by\ 12\\\\
9x-18+3x=16*4\\\\
12x=64+18\\\\
12x=82\ \ \ |Divide\ by\ 12\\\\
\boxed{x=6\frac{5}{6}}[/tex]