Answer :
[tex]\frac{7}{8}p-\frac{1}{4}=\frac{1}{2}p \\\\ \frac{7p}{8}-\frac{1}{4}^{(2}=\frac{p}{2}^{(4} \\\\ 7p-2=4p\\\\7p-4p=2 \\\\3p=2\\\\ \boxed{p=\frac{2}{3}}[/tex]
if you mean [tex] \frac{7}{8p} - \frac{1}{4}=\frac{1}{2p}[/tex]
then multiply by p to give [tex]\frac{7}{8}-\frac{p}{4}=\frac{1}{2}[/tex]
then multiply by 8 to give [tex]7-2p=4[/tex]
subtract 7 [tex]-2p=-3[/tex]
divide by -2 [tex]p=\frac{3}{2}[/tex]
if you mean [tex](\frac{7}{8})p-\frac{1}{4}=(\frac{1}{2})[/tex]
then multiply by 8 to give [tex]7p-2=4p[/tex]
subtract 4p [tex]3p-2=0[/tex]
add 2 [tex]3p=2[/tex]
then divide by 3 [tex]p=\frac{2}{3}[/tex]
hope that helps
then multiply by p to give [tex]\frac{7}{8}-\frac{p}{4}=\frac{1}{2}[/tex]
then multiply by 8 to give [tex]7-2p=4[/tex]
subtract 7 [tex]-2p=-3[/tex]
divide by -2 [tex]p=\frac{3}{2}[/tex]
if you mean [tex](\frac{7}{8})p-\frac{1}{4}=(\frac{1}{2})[/tex]
then multiply by 8 to give [tex]7p-2=4p[/tex]
subtract 4p [tex]3p-2=0[/tex]
add 2 [tex]3p=2[/tex]
then divide by 3 [tex]p=\frac{2}{3}[/tex]
hope that helps
