Answer :
Hello,
We know that th formula for the area of a rectangle is: [tex]A=b*h[/tex]
Now, the problem in this excercise is that there is no restriction on the values that b and h can take, so, they can take any value provided that it meets: [tex]b*h=12 cm^{2} [/tex]
for example:
[tex]lenght= \frac{12}{3}cm \,\,\,\,\,\,and\,\,\,\,width= 3 cm \\ \\ A=\frac{12}{3}cm*3cm \\ A=12 cm^{2} [/tex]
But if they can only take intenger values, what we have to do is to descompose 12, and then we can analyze the possible solutions.
12 | 2
6 | 2
3 | 3
1
12= 2 *2*3
first option:
12=4*3
Answer: lenght= 4cm and width= 3cm or vice versa
second option:
12=2*6
Answer: lenght= 6cm and width= 2cm or vice versa
We know that th formula for the area of a rectangle is: [tex]A=b*h[/tex]
Now, the problem in this excercise is that there is no restriction on the values that b and h can take, so, they can take any value provided that it meets: [tex]b*h=12 cm^{2} [/tex]
for example:
[tex]lenght= \frac{12}{3}cm \,\,\,\,\,\,and\,\,\,\,width= 3 cm \\ \\ A=\frac{12}{3}cm*3cm \\ A=12 cm^{2} [/tex]
But if they can only take intenger values, what we have to do is to descompose 12, and then we can analyze the possible solutions.
12 | 2
6 | 2
3 | 3
1
12= 2 *2*3
first option:
12=4*3
Answer: lenght= 4cm and width= 3cm or vice versa
second option:
12=2*6
Answer: lenght= 6cm and width= 2cm or vice versa
