Answer :
Acceleration (magnitude anyway) = (change in speed) / (time for the change) .
Change in speed = (10 - 30) = -20 m/s
Time for the change = 4.0sec
Magnitude of acceleration = -20/4 = -5 m/s²
Change in speed = (10 - 30) = -20 m/s
Time for the change = 4.0sec
Magnitude of acceleration = -20/4 = -5 m/s²
Hello!
The speed of a car is decreased uniformly from 30. meters per second to 10. meters per second in 4.0 seconds. What was the car's acceleration ?
We have the following data:
V (final velocity) = 10 m/s
Vo (initial velocity) = 30 m/s
ΔV (speed interval) = V - Vo → ΔV = 10 - 30 → ΔV = - 20 m/s
ΔT (time interval) = 4.0 seconds
a (average acceleration) = ? (in m/s²)
Formula:
[tex]\boxed{a = \dfrac{\Delta{V}}{\Delta{T}}}[/tex]
Solving:
[tex]a = \dfrac{\Delta{V}}{\Delta{T}}[/tex]
[tex]a = \dfrac{-20\:\dfrac{m}{s}}{4.0\:s}[/tex]
[tex]\boxed{\boxed{a = - 5\:\frac{m}{s^2}}}\:\:\:\:\:\:\bf\green{\checkmark}[/tex]
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