Answer :
Okay, so first you are going to decide whether to solve for x or solve for y. I am going to solve for x. In order to do so, you must get x by itself.
[tex]2x-y=-6[/tex]
[tex]2x=y-6[
[tex]3x-4y=-4[/tex]
[tex]3x=4y-4 \\ x= \frac{4y-4}{3} [/tex]
The next step is to set both equations equal to each other in order to find y.
\frac{y-[tex]\frac{y-6}{2}= \frac{4y-4}{3} \\ 3(y-6)=2(4y-4) \\ 3y-18=8y-8 \\ -10=5y \\ y=-2[/tex]6}{2} [/tex]
So now you know that y=-2. The next part is substitution. All you have to do is pick on of the equations and plug in the y value to get the x value.
So your answer to the question is (-4,-2). I hope I've helped you understand how to solve these types of problems. If you have any questions, don't hesitate to ask.
[tex]2x-y=-6[/tex]
[tex]2x=y-6[
[tex]3x-4y=-4[/tex]
[tex]3x=4y-4 \\ x= \frac{4y-4}{3} [/tex]
The next step is to set both equations equal to each other in order to find y.
\frac{y-[tex]\frac{y-6}{2}= \frac{4y-4}{3} \\ 3(y-6)=2(4y-4) \\ 3y-18=8y-8 \\ -10=5y \\ y=-2[/tex]6}{2} [/tex]
So now you know that y=-2. The next part is substitution. All you have to do is pick on of the equations and plug in the y value to get the x value.
So your answer to the question is (-4,-2). I hope I've helped you understand how to solve these types of problems. If you have any questions, don't hesitate to ask.
