Answer :
This problem can be solved using the point-slope formula:
[tex]y-y_{1}=m(x-x_{1})[/tex]
Where m is the slope
x₁ is the x value provided and
y₁ is the y value provided.
Since this line is parallel, we know it will have the same slope as the original line, which is -3. The x₁ value is -1, and the y₁ value is 6. Plug these numbers into the equation and solve:
[tex]y-y_{1}=m(x-x_{1})\\ y-6=-3(x+1)\\ y-6=-3x-3\\ \\y=-3x+3[/tex]
[tex]y-y_{1}=m(x-x_{1})[/tex]
Where m is the slope
x₁ is the x value provided and
y₁ is the y value provided.
Since this line is parallel, we know it will have the same slope as the original line, which is -3. The x₁ value is -1, and the y₁ value is 6. Plug these numbers into the equation and solve:
[tex]y-y_{1}=m(x-x_{1})\\ y-6=-3(x+1)\\ y-6=-3x-3\\ \\y=-3x+3[/tex]
