Answer :
[tex] \left \{ {{x-2y=0} \atop {y=2x-3}} \right. \\\\Substitute\ second\ equation\ to\ first:\\\\x-2(2x-3)=0\\x-4x+6=0\\-3x=-6\ \ \ \ \ |:-3\\x=2\\\\y=2\cdot2-3\\y=4-3=1\\\\ \left \{ {{y=1} \atop {x=2}} \right. [/tex]
x - 2y = 0
y = 2x - 3
You subsitute. Since, y = 2x - 3, then you fill what y equals in for the y on the top equation.
x - 2 (2x - 3) = 0 :Distribute
x - 4x + 6 = 0 :Combine Like Terms
-3x + 6 = 0 :Subtract the 6 over to the 0
-6 -6
(-3x = -6) ÷ -3 :Now, divide the whole equation by -3
x = 2
Then, you want to get y, so you fill in the x that you got before into the bottom equation.
y = 2 ( 2) - 3 :Now, multiply 2 × 2 (Because of PEMDAS)
y = 4 - 3
y = 1
Your final answer is:
(2, 1)
y = 2x - 3
You subsitute. Since, y = 2x - 3, then you fill what y equals in for the y on the top equation.
x - 2 (2x - 3) = 0 :Distribute
x - 4x + 6 = 0 :Combine Like Terms
-3x + 6 = 0 :Subtract the 6 over to the 0
-6 -6
(-3x = -6) ÷ -3 :Now, divide the whole equation by -3
x = 2
Then, you want to get y, so you fill in the x that you got before into the bottom equation.
y = 2 ( 2) - 3 :Now, multiply 2 × 2 (Because of PEMDAS)
y = 4 - 3
y = 1
Your final answer is:
(2, 1)
