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A candy store wants to create a mix of two hard candies. One is priced at $5.45 per pound, and the other is priced a $7.33 per pound. How many pounds of the $7.33 candy should be mixed with 11 pounds of the $5.45 candy to sell the mixture for $6.14 per pound.

Solve and explain please. 
Also make an equation first. Thanks.



Answer :

luana
[tex]x-\ amount\ of\ candy\ which\ cost\ 5,45\$\\\\y-\ amount\ of\ candy\ which\ cost\ 7,33\$\\\\ 7,33*y+11*5,45=6,14(11+y)\\\\ 7,33y+59,95=67,54+6,14y\ \ \ \ | subtract\ 6,14y\\\\ 1,19y=67,54-59,95\\\\ 1,19y=7,59\ \ \ \ | divide\ by\ 1,19\\\\y=6,38\ pound\\\\ 6,38\ pounds\ should\ be\ mixed\ with\ those\ wich\ cost\ 5,45.[/tex]

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