Answer :
We want to find x in times of y and z, so we want to have only 1 x on the LHS of equation, so
3x-7y=z /+7z (add 7z both sides)
3x=z+7z /:3 (divide 3 both sides)
[tex]x= \frac{z+7y}{3} [/tex] - its the result.
3x-7y=z /+7z (add 7z both sides)
3x=z+7z /:3 (divide 3 both sides)
[tex]x= \frac{z+7y}{3} [/tex] - its the result.
