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How much tension must a rope withstand if used to accelerate a 960-kg car from rest horizontally along a frictionless surface to 1.20 m/s in 5 seconds?



Answer :

Use a=(dv/dt)         (change in velocity/ change in time)=acceleration
(1.2/5)=acceleration

F=ma (Newton's second law, Force= Mass x Acceleration

=960 x 0.24     F=230.4N If  T<230.4N then the tow rope will hold

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