Answer :
Ions and charges= Al+3 SO3-2
The charges must add up to zero, in order for two +3 aluminum ions to cancel out three -2 sulfite ions.
Al+3 Al+3 SO3-2 SO3-2 SO3-2
So simply put : Al2(SO3)3
The charges must add up to zero, in order for two +3 aluminum ions to cancel out three -2 sulfite ions.
Al+3 Al+3 SO3-2 SO3-2 SO3-2
So simply put : Al2(SO3)3
