Answer :
1. An 8-kilogram bowling ball is rolling in a straight line toward you. If its momentum is 16 kg•m/s, how fast is it traveling?
momentum = mass x velocity
16 = 8 x velocity
velocity = 2 m/s
2.A beach ball is rolling in a straight line toward you at a speed of 0.5 m/sec. Its momentum is 0.25 kg•m/s. What is the mass of the beach ball?
momentum = mass x velocity
0.25 = m x 0.5
mass = 0.5 kg
3.A 4,000-kilogram truck travels in a straight line at 10.0 m/s. What is its momentum?
Momentum = (mass) x (speed) = (4,000) x (10) = 40,000 kilogram-meters/second
4.A 1,400-kilogram car is also traveling in a straight line. Its momentum is equal to that of the truck in the previous question. What is the velocity of the car?
40,000 kilogram-meters/second = 1400 x velocity
velocity = 28.6 m/s
5.Which would take more force to stop in 10 seconds: an 8.0-kilogram ball rolling in a straight line at a speed of 0.2 m/s or a 4.0-kilogram ball rolling along the same path at a speed of 1.0 m/s?
F1 = 8 x 0.2 / 10 = 0.16 N
F2 = 4 x 1.0 / 10 = 0.4 N ----> take more force
6.The momentum of a car traveling in a straight line at 20 m/s is 24,500 kg•m/s. What is the car’s mass?
24500 = mass x 20
mass = 1225 kg
7.Another pitcher throws the same baseball in a straight line. Its momentum is 2.1 kg•m/s. What is the velocity of the ball?
2.1 = 0.5 x velocity
velocity = 4.2 m/s
8 A 1-kilogram turtle crawls in a straight line at a speed of 0.01 m/s. What is the turtle’s momentum?
momentum = 1 x 0.01 = 0.01 kg m/s
momentum = mass x velocity
16 = 8 x velocity
velocity = 2 m/s
2.A beach ball is rolling in a straight line toward you at a speed of 0.5 m/sec. Its momentum is 0.25 kg•m/s. What is the mass of the beach ball?
momentum = mass x velocity
0.25 = m x 0.5
mass = 0.5 kg
3.A 4,000-kilogram truck travels in a straight line at 10.0 m/s. What is its momentum?
Momentum = (mass) x (speed) = (4,000) x (10) = 40,000 kilogram-meters/second
4.A 1,400-kilogram car is also traveling in a straight line. Its momentum is equal to that of the truck in the previous question. What is the velocity of the car?
40,000 kilogram-meters/second = 1400 x velocity
velocity = 28.6 m/s
5.Which would take more force to stop in 10 seconds: an 8.0-kilogram ball rolling in a straight line at a speed of 0.2 m/s or a 4.0-kilogram ball rolling along the same path at a speed of 1.0 m/s?
F1 = 8 x 0.2 / 10 = 0.16 N
F2 = 4 x 1.0 / 10 = 0.4 N ----> take more force
6.The momentum of a car traveling in a straight line at 20 m/s is 24,500 kg•m/s. What is the car’s mass?
24500 = mass x 20
mass = 1225 kg
7.Another pitcher throws the same baseball in a straight line. Its momentum is 2.1 kg•m/s. What is the velocity of the ball?
2.1 = 0.5 x velocity
velocity = 4.2 m/s
8 A 1-kilogram turtle crawls in a straight line at a speed of 0.01 m/s. What is the turtle’s momentum?
momentum = 1 x 0.01 = 0.01 kg m/s
The momentum is given as the product of mass and velocity.
1) mass (m) = 8 Kg
momentum(p) = 16 kg•m/s
velocity(v) = ?
p = mv
v =p/m
v = 16 kg•m/s/8 Kg
v = 2 m/s
2) p = mv
m = ?
v = 0.5 m/sec
p = 0.25 kg•m/s
m = p/v
m = 0.25 kg•m/s/0.5 m/sec
m = 0.5 Kg
3) p = mv
m = 4,000-kilogram
v = 10.0 m/s
p = 4000 Kg × 10.0 m/s
p = 40000 Kg.m/s
4) m = 1,400-kilogram
v = ?
p = 40000 Kg.m/s
v = p/m
v = 40000 Kg.m/s/1,400-kilogram
v = 28.57 m/s
5) a = v - u/t
v = 0 m/s
u = 0.2 m/s
t = 10 s
a = 0 m/s - 0.2 m/s /10 s
a = -0.02 m/s^2
F = ma
F = 8 Kg × -0.02 m/s^2
F = - 0.16 N
Also;
a = v - u/t
v = 0 m/s
u = 1.0 m/s
t = 10 s
a = 0 - 1.0 m/s/10 s
a = -0.1 m/s^2
F = ma
F = 4 Kg × -0.1 m/s^2
F = -0.4 N
The 4.0-kilogram ball rolling along the same path at a speed of 1.0 m/s will take a greater force to stop.
6) p = mv
p = 24,500 kg•m/s
v = 20 m/s
m = ?
m = p/v
m = 24,500 kg•m/s/20 m/s
m = 1225 Kg
7) p = 2.1 kg•m/s
m = 1225 Kg
v = ?
p = mv
v = p/m
v = 2.1 kg•m/s/1225 Kg
v = 0.0017 m/s
8) p = mv
p = ?
m = 1-kilogram
v = 0.01 m/s
p = 1-kilogram × 0.01 m/s
p = 0.01 Kg.m/s
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