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NaHCO3 (s) + HC2H3O2 (aq) = NaC2H3O2 (aq) + H2O (I) + CO2 (g)
Using the above formula, if I used 0.100L of 0.83 M HC2H3O2 (aq) (0.83 mol per 1 L of solution), how much carbon dioxide would be produced?



Answer :

Jerboa

Moles=volume*concentration   
         =0.1*.83
         =.083 Moles of HC2H3O2
Mole ratio between HC2H3O2 and CO2 is 1:1
This means .083 Moles of CO2

Mass =Moles*Rfm of CO2
         =.083*(12+16+16)
         =3.7grams

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