Answer :

konrad509
[tex]y=3x^2+2x\\ y=x(3x+2)\\ y=x(x+\frac{2}{3})\\ x=0 \vee x=-\frac{2}{3}\\\\ f(x)=5x^2-25x+30\\ f(x)=5(x^2-5x+6)\\ f(x)=5(x^2-2x-3x+6)\\ f(x)=5(x(x-2)-3(x-2))\\ f(x)=5(x-3)(x-2)\\ x=3 \vee x=2 [/tex]

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