Answer :
[tex]3=a\cdot(-1)^2+b\cdot(-1)+c\\
8=a\cdot3^2+b\cdot3+c\\
2=a\cdot0^2+b\cdot0+c\\\\
3=a-b+c\\
8=9a+3b+c\\
2=c\\\\
3=a-b+2\\
8=9a+3b+2\\\\
a=b+1\\
9a+3b=6\\\\
9(b+1)+3b=6\\
9b+9+3b=6\\
12b=-3\\
b=-\frac{3}{12}=-\frac{1}{4}\\\\
a=-\frac{1}{4}+1\\
a=\frac{3}{4}\\\\
\boxed{y=\frac{3}{4}x^2-\frac{1}{4}x+2}[/tex]
