Answer :
[tex]5)\ -2\times\frac{3}{7}=-\frac{2\times3}{7}=-\frac{6}{7}\\\\6)\ -2\frac{2}{3}\times4\frac{1}{10}=-\frac{8}{3}\times\frac{41}{10}=-\frac{4}{3}\times\frac{41}{5}=-\frac{164}{15}=-10\frac{14}{15}\\\\7)\ -2\frac{1}{5}\times(-1\frac{3}{4})=-\frac{11}{5}\times(-\frac{7}{4})=\frac{77}{20}=3\frac{17}{20}\\\\8)\ -1\frac{1}{4}\times9=-\frac{5}{4}\times9=-\frac{45}{4}=-11\frac{1}{4}\\\\9)\ -1\frac{5}{7}\times(-2\frac{1}{2})=-\frac{12}{7}\times(-\frac{5}{2})=\frac{6}{7}\times\frac{5}{1}=\frac{30}{7}=4\frac{2}{7}[/tex]
[tex]1)\ -2\frac{3}{8}\times2\frac{1}{2}=-\frac{19}{8}\times\frac{5}{2}=-\frac{95}{16}=-5\frac{15}{16}[/tex]
[tex]1)\ -2\frac{3}{8}\times2\frac{1}{2}=-\frac{19}{8}\times\frac{5}{2}=-\frac{95}{16}=-5\frac{15}{16}[/tex]
