Answer :
One hour is sixty minutes, so if he runs nine miles in one hour and he only runs for twenty minutes than it should be 9/3= 3 miles
First we have to know how much of one hour is 20 min.
To get it, we have to dividie 20min by 60 min (60 min=1hour), so
20:60=[tex] \frac{20}{60}= \frac{2}{6}= \frac{1}{3} [/tex]
We know that
[tex]v= \frac{s}{t} [/tex]
where v is velocity, s is distance and t is time
We can modify formula to get
[tex]v= \frac{s}{t} \\ v*t=s [/tex]
Now we just have to substitute our data ( t=1/3 and v=9 miles/hour)
s=[tex] \frac{1}{3}*9 [/tex]=3 miles - its the result
To get it, we have to dividie 20min by 60 min (60 min=1hour), so
20:60=[tex] \frac{20}{60}= \frac{2}{6}= \frac{1}{3} [/tex]
We know that
[tex]v= \frac{s}{t} [/tex]
where v is velocity, s is distance and t is time
We can modify formula to get
[tex]v= \frac{s}{t} \\ v*t=s [/tex]
Now we just have to substitute our data ( t=1/3 and v=9 miles/hour)
s=[tex] \frac{1}{3}*9 [/tex]=3 miles - its the result
