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Acceleration is sometimes expressed in multiples of g, where g=9.8 m/s2 is the acceleration due to gravity. In a car crash, the cars velocity changes from 30 m/s to 0 m/s in 0.15s. In terms of g, what is the acceleration of the car.



Answer :

ollieboyne
[tex]a = \frac{\Delta v}{t} \\a= \frac{30}{0.15} \\a = 200 ms^-2 [/tex]

in terms of g:

[tex]a = 200/9.8 g= 20.40...g a = 20.4g (3s.f)[/tex]

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