Answer :
For this case we have the following function:
[tex]f(x) = -5x^2 - 20x - 10 [/tex]
To find the axis of symmetry, the first thing to do is to derive the function.
We have then:
[tex]f '(x) = -10x - 20 [/tex]
Equaling zero we have:
[tex]-10x - 20 = 0 [/tex]
We clear the value of x.
We have then:
[tex]-10x = 20 x = -20/10 x = -2 [/tex]
Answer:
The axis of symmetry is given by:
x = -2
[tex]f(x) = -5x^2 - 20x - 10 [/tex]
To find the axis of symmetry, the first thing to do is to derive the function.
We have then:
[tex]f '(x) = -10x - 20 [/tex]
Equaling zero we have:
[tex]-10x - 20 = 0 [/tex]
We clear the value of x.
We have then:
[tex]-10x = 20 x = -20/10 x = -2 [/tex]
Answer:
The axis of symmetry is given by:
x = -2
Answer:
x= -2 is the axis of symmetry for [tex]f(x) = -5x^2-20x-10[/tex]
Step-by-step explanation:
A quadratic equation is in the form of [tex]y =ax^2+bx+c[/tex] .......[1],
then the axis of symmetry is given by:-
[tex]x = -\frac{b}{2a}[/tex] ....[2]
As per the statement:
[tex]f(x) = -5x^2-20x-10[/tex]
On comparing with equation [1] we have;
a = -5, b = -20 and c = -10
Substitute these values in [2] we have;
[tex]x = -\frac{-20}{2 \cdot (-5)}[/tex]
⇒[tex]x = -\frac{-20}{-10}[/tex]
Simplify:
x = -2
Therefore, the axis of symmetry for the given function is, x= -2.
