Lilkate98 Lilkate98

17-11-2014
Mathematics

Answered

Show that each statement is true:
Cos^4X-sin^4X=2cos^2X-1

Answer :

18-11-2014

[tex]cox^4x-sin^4x=2cos^2x-1\\\\ (cosx^2-sin^2x)(cosx^2x+sin^2x)=2cos^2x-1\\\\ cosx^2-sin^2x*1=2cos^2x-1\ \ \ | subtract\ 2cos^2x\\\\ -cosx^2-sin^2x=-1\ \ \ | multiply\ by\ -1\\\\ cosx^2+sin^2x=1\\\\ 1=1[/tex]

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