Answer :
First bring all terms to one side left equal to zero
X^2 + 6x - 40
Now we need to factor this, meaning find 2 binomials that when multiplied result in the original.
Start with (x )(x ) because x*x= x^2
The last part is negative, so we can turn it into (x+ )(x- )
Now we need to find two numbers that add to 6 and multiply to -40
The numbers that work are 10 and -4
Now we put those in to get (x+10)(x-4)=0
Now it is factored.
Because they equal 0, that means that one or both of the expressions inside the parentheses must equal zero
So we can split it up into x+10=0 and x-4=0
Solving for those we get x=-10 or x=4
Final answer:
X=-10 or x=4
X^2 + 6x - 40
Now we need to factor this, meaning find 2 binomials that when multiplied result in the original.
Start with (x )(x ) because x*x= x^2
The last part is negative, so we can turn it into (x+ )(x- )
Now we need to find two numbers that add to 6 and multiply to -40
The numbers that work are 10 and -4
Now we put those in to get (x+10)(x-4)=0
Now it is factored.
Because they equal 0, that means that one or both of the expressions inside the parentheses must equal zero
So we can split it up into x+10=0 and x-4=0
Solving for those we get x=-10 or x=4
Final answer:
X=-10 or x=4
