Answer :
[tex]2x^2-x=1\ \ \ | subtract\ 1\\\\
2x^2-x-1=0\\\\use\ factorization:\\
write\ -x\ as\ x-2x\\\\
2x^2+x-2x-1=0\\\\
x(2x+1)-1(2x-1)=0\\\\
(x-1)(2x+1)=0\\\\
x=1\ \ \ or\ \ \ 2x=-1\\\\
x=1\ \ \ or \ \ \ x=-\frac{1}{2}[/tex]
First move all terms to the same side.
2x^2-x-1=0
Factor this to get
(2x+1)(x-1)=0
Separate into
2x+1=0 and x-1=0
Solve these two to get
X=-1/2 or x=1
Final answer:
X=-1/2 or x=1
2x^2-x-1=0
Factor this to get
(2x+1)(x-1)=0
Separate into
2x+1=0 and x-1=0
Solve these two to get
X=-1/2 or x=1
Final answer:
X=-1/2 or x=1
