Answer :
[tex]D:3x+1\geq 0\wedge x-1\geq 0\\
D:3x\geq-1 \wedge x\geq1\\
D:x\geq-\frac{1}{3} \wedge x\geq1\\
D:x\geq1\\
\sqrt{3x+1}=x-1\\
3x+1=(x-1)^2\\
3x+1=x^2-2x+1\\
x^2-5x=0\\
x(x-5)=0\\
x=0 \vee x=5
[/tex]
The solution is 5.
The extraneous solution is 0.
The solution is 5.
The extraneous solution is 0.