Answer :
Δp=mΔv
400 N.s = (90kg) (vf-9m/s)
400 = 90 vf - 810
400 + 810 = 90 vf
1210 = 90vf
vf= 13.4 m/s
400 N.s = (90kg) (vf-9m/s)
400 = 90 vf - 810
400 + 810 = 90 vf
1210 = 90vf
vf= 13.4 m/s
Answer: The change velocity of the tight end is 4.44 m/s
Explanation:
Mass of the tight end = 90 kg
Initial velocity =[tex]u[/tex] = 9.0 m/s
Final velocity =[tex]v[/tex]
[tex]Impulse=Force\times Time[/tex]
[tex]Impulse=Mass \times acceleration\times Time[/tex]
[tex]a=\frac{dv}{dt}=\frac{[v-u]}{t}[/tex]
[tex]impulse=Mass \times [v-u][/tex]
[tex]400 Nm=90 kg\times[v-9.0 m/s][/tex]
[tex]v=13.44 m/s[/tex]
Change in velocity = 13.44 m/s - 9m/s = 4.44 m/s
The change velocity of the tight end is 4.44 m/s
