A ski jumper competing for an Olympic gold-medal wants to jump a horizontal distance of 135 m the take off point of the ski jump is that a height of 25 m with what horizontal speed must he leave the jump



Answer :

Time before landing = sqrt ( 2 x height / gravity ), sqrt ( 2 x 25 / 9.81) = 2.26
distance / time = avg speed
135 / 2.26 = 60~ m/s 

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