Answer :
[tex]1)\\
3y+1=16\ \ \ \ | subtract\ 1\\\\
3y=15\ \ \ \ | divide\ by\ 3\\\\
y=5\\\\\
2)\\
18=4k+6\ \ \ \ | subtract\ 6\\\\
12=4k\ \ \ \ | divide\ by\ 4\\\\
k=3[/tex]
3y+1=16
Subtract 1 from both sides
(3y+1)-1=(16)-1
3y=15
Divide both sides by 3
(3y)/3=(15)/3
Y=5
18=4k+6
Subtract 6 from both sides
(18)-6=(4k+6)-6
12=4k
Divide both sides by 4
(12)/4=(4k)/4
3=k
Final answer:
1) y=5
2) k=3
Subtract 1 from both sides
(3y+1)-1=(16)-1
3y=15
Divide both sides by 3
(3y)/3=(15)/3
Y=5
18=4k+6
Subtract 6 from both sides
(18)-6=(4k+6)-6
12=4k
Divide both sides by 4
(12)/4=(4k)/4
3=k
Final answer:
1) y=5
2) k=3
