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A conveyor belt carries supplies from the first floor to the second floor , which is 15ft higher. The belt makes a 60degree angle with the ground. How far do the supplies travel from one end of the conveyor belt to the other? Round to the nearest foot.
If the belt moves at 75ft\min, how long, to the nearest tenth of a minute does it take the supplies to move to the second floor? A: 17ft, 0.2min B:21 ft;12.8min C:26ft; 24min or D:9ft; 0.9min



Answer :

Well this is a simple trig question, for this use the sine rule:
Whatever you are looking for will be on the top so in this case length will be on the top.
a/sinA = b/sinB, a = 15, b=b, A = 60 and B = 90 (Assumption)
Re-arrange for b:
b = a(sinB)/SinA = 15(sin60)/sin90
b = 13ft

v = s/t where v = velocity, s = distance and t = time taken
we are looking for t so:
t = s/v = 13/75
t = 0.173

So the time in minutes would be 0.173 x 60 = 10.4 minutes

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