Answer :
36x^(2)-25. Now, we notice that 36 and 25 are squares of 6 and 5 respectively, as well as x^(2) being the square of x.
We know that (x+y)(x-y)=(x^(2)-y^(2)) or x(squared) minus y(squared)
So, we can factor the equation to be (6x+5)(6x-5) which is the same as 36x^(2)-25.
Hope this helps!
We know that (x+y)(x-y)=(x^(2)-y^(2)) or x(squared) minus y(squared)
So, we can factor the equation to be (6x+5)(6x-5) which is the same as 36x^(2)-25.
Hope this helps!
Factor [tex]36 x^{2} -25[/tex]
This is in the form of [tex]a^{2} - b^{2} [/tex]
There is a special factorization of [tex]a^{2} - b^{2} [/tex] and it is [tex](a+b)(a-b)[/tex].
Our [tex] a^{2} = 36 x^{2} [/tex] so [tex]a=6x[/tex]
Our [tex] b^{2}=25 [/tex] so [tex]b=5[/tex]
Plugging this into (a+b)(a-b) we get (6x+5)(6x-5).
Hope this helps. If it does, please consider making this the brainliest answer. I am trying to be virtuoso. Thanks!
This is in the form of [tex]a^{2} - b^{2} [/tex]
There is a special factorization of [tex]a^{2} - b^{2} [/tex] and it is [tex](a+b)(a-b)[/tex].
Our [tex] a^{2} = 36 x^{2} [/tex] so [tex]a=6x[/tex]
Our [tex] b^{2}=25 [/tex] so [tex]b=5[/tex]
Plugging this into (a+b)(a-b) we get (6x+5)(6x-5).
Hope this helps. If it does, please consider making this the brainliest answer. I am trying to be virtuoso. Thanks!
