Answer :
mass of water: 8 * 18 g = 144 g
mass of Ba(OH)2 = 171.3 g
total mass: 144 g + 171.3 g = 315.3 g
percentage of water: (144 g / 315.3 g) * 100% = 45.67%
mass of Ba(OH)2 = 171.3 g
total mass: 144 g + 171.3 g = 315.3 g
percentage of water: (144 g / 315.3 g) * 100% = 45.67%
