ayah1
Answered

Are these answers correct?

1. A gas occupies 30 L at 760 mm Hg. What is its volume at 350 mm Hg?

P1*V1 = P2*V2

760 mm Hg *30 L = 350 mm Hg * V2

V2 = 22800 mm Hg*L/350 mm Hg

V2 = about 65.14 L


2. A gas occupies 500 mL at 1 atm. What is its pressure if the volume becomes 1500 mL?

P1*V1 = P2*V2

1 atm*500 mL = P2*1500 mL

500 atm*mL/1500 mL = P2

P2 = 1/3 atm


3. If a gas occupies 250 mL at 25°C, what will its volume be at 57°C?

25°C + 273 = 298°K; 57°C + 273 = 330°K

V1/T1 = V2/T2

250 mL/298°K = V2/330°K

0.84 mL/k*330°K = V2

V2 = about 276.85 mL

4. What was the original temperature of a 2 L sample of gas if it initially had the volume 5 L at 27°C?

27°C + 273 = 298°K

V1/T1 = V2/T2

5 L/298°K = 2 L/T2

2 L/(0.017 L/K)= T2

T2 = 119.2°K = -153.8°C

5. At what pressure would 100 mL of a gas be found if it began at 500 mL at 2.5 atm?

P1*V1 = P2*V2

2.5 atm*500 mL = P2*100 mL

125 atm*mL/100 mL = P2

P2 = 1.25 atm

6. What is the volume of a gas at 275 mm Hg if it occupied 750 mL at 1000 mm Hg?

P1*V1 = P2*V2

1000 mm Hg*750 mL = 275 mm Hg*V2

750000 mm Hg*mL/275 mm Hg = V2

V2 = about 2727. 27 mL

7. A gas occupies 60 L at 250°K and 1 atm. What is its volume at 250°C and 1.5 atm?

250°C + 273 = 523°K

P1*V1/T1 = P2*V2/T2

1 atm*60 L/250°K = 1.5 atm*V2/523°K

0.24 (atm*L/K)*523°K = 1.5 atm*V2

125.52 (atm*L)/1.5 atm = V2

V2 = 83.68 L

8. What is the final temperature in Celsius of a gas occupying 3.25 L at 750 mm Hg if it occupied 2250 mL at 37°C and 600 mm Hg?

37°C + 273 = 310°K; 2250 mL = 2.25 L

P1*V1/T1 = P2*V2/T2

600 mm Hg*2.25 L/310°K = 750 mm Hg*3.25 L/T2

2437.35 mm Hg*L/ (4.35 mm Hg*L/K) = T2

T2 = 559.69°K
T2 = about 286.69°C



Answer :

I saw a slight error in number 8. 750*3.25=2437.5 not 2437.35. That threw your final answer off by a little more than half a °C. Other than that, I didn't see anything wrong.

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