Answer :
C. 2
Because
3x+2(2)=13
3x+4=13
3x=9
x=3
None of the other solutions work out so that both x and y are integers.
Because
3x+2(2)=13
3x+4=13
3x=9
x=3
None of the other solutions work out so that both x and y are integers.
They are all integers so...
first lets substitute
A.3x=13
X=13/3
b.3x+2=13
3x=11
x=11/3
c.3x+4=13
3x=9
x=3
d.3x+6=13
3x=7
x=7/3
E.3x+8=13
3x=5
x=5/3
therefore the possible is letter c because it must be an integer and the definition of integer states that it is not a decimal nor a fraction
first lets substitute
A.3x=13
X=13/3
b.3x+2=13
3x=11
x=11/3
c.3x+4=13
3x=9
x=3
d.3x+6=13
3x=7
x=7/3
E.3x+8=13
3x=5
x=5/3
therefore the possible is letter c because it must be an integer and the definition of integer states that it is not a decimal nor a fraction
