Answer :

luana
[tex]\frac{1}{5}>d+\frac{4}{5}\ \ \ \ \ \ \ \ |subtract\ \frac{4}{5}\\\\\frac{1}{5}-\frac{4}{5}>d\\\\d<-\frac{3}{5}\\\\d\in(-\infty,-\frac{3}{5})[/tex]

Other Questions