[tex]9x+3y=8\ \ \ | subtract\ 9x\\\\
3y=8-9x\ \ \ | divide\ by\ 3\\\\
y=-3x+\frac{8}{3}\\\\new\ line:\y=ax+b\\\\line\ is\ parallel\ when\ a=-3\\\\
y=-3x+b\ \ \ | substitute\ point \ (-1,-4)\\\\
-4=-3*(-1)+b\\\\
-4=3+b\ \ \ | subtract\ 3\\\\
b=-7\\\\Line\ : \ y=-3x-7[/tex]
