Answer :

Geekhawk
In [tex] \frac{50}{32} [/tex], you must find a common factor.
Since they are both even, 2 is a factor.

Divide both the numerator and denominator by 2

[tex] \frac{50}{32} [/tex]÷[tex] \frac{2}{2} [/tex]=[tex] \frac{25}{16} [/tex]

[tex] \frac{25}{16} [/tex] is the simplified improper fraction

But to find the mixed fraction, divide the numerator by the denominator

25÷16= [tex]1 \frac{56}{100} [/tex]

Put aside the whole number(1)

Since they are even numbers, 2 is a factor

[tex] \frac{56}{100} [/tex]÷[tex] \frac{2}{2} [/tex]=[tex] \frac{28}{50} [/tex]

Again, both the numerator and denominator are even numbers. So divide them by [tex] \frac{2}{2} [/tex] again

[tex] \frac{28}{50} [/tex]÷[tex] \frac{2}{2} [/tex]=[tex] \frac{14}{25} [/tex]

So get the whole number and add it to the answer

[tex]1+ \frac{14}{25} =1 \frac{14}{15} [/tex]

[tex]1 \frac{14}{25} [/tex] is your answer as a mixed fraction or [tex] \frac{25}{16} [/tex] as an improper fraction


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