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Solve using elimination method.
2x+3y=7 and 4x+2y =-6
A) one of (32,-19) or (6,-5)
B) one of (0,1) or (2,0)
C) one of (-3,1) or (2,1)
D) one of (4,–1) or (-4,5)



Answer :

konrad509
[tex]2x+3y=7|\cdot(-2)\\ 4x+2y=-6\\\\ -4x-6y=-14\\ 4x+2y=-6\\ -------\\ -4y=-20\\ y=5\\\\ 2x+3\cdot5=7\\ 2x+15=7\\ 2x=-8\\ x=-4[/tex]

D

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