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a jumping spider jumps from a log on the ground below. its height , h, in cm as a function of time ,t, in seconds since it jumped can be modeled by the function h(f)=-490t2+75t+12. when does the spider land on the ground? and what is the height of the spider 0.05 s after it jumps?



Answer :

bayjo98241
Inorder to find the height, you miust plug in 0.05s for all times (t)
h(f) = -490t^2 + 75t + 12
h(f) = -490 • 0.05^2 + 75 • 0.05 + 12

Next follow PEMDAS from left to right.
(MD reversible, AS reversible)
(parentheses, exponents, multiply, divide, add, subtract)
parentheses~ nothing to simplify with parentheses
exponents~ h(f) = -490 • 0.0025 + 75 • 0.05 +12
multiply~  h(f) = -1.225 + 3.75 +12
divide~ nothing to simplify with division
add~ h(f) = 14.525
subtract~ nothing to simplify with subtraction

DON'T FORGET UNITS!

Answer: h(f) = 14.525 cm



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